2x^2+3x-11=2(x-1)(x+1)

Solution for 2x^2+3x-11=2(x-1)(x+1) equation:

2x^2+3x-11=2(x-1)(x+1)

We move all terms to the left:

2x^2+3x-11-(2(x-1)(x+1))=0

We use the square of the difference formula

2x^2+x^2+3x+1-11=0

We add all the numbers together, and all the variables

3x^2+3x-10=0

a = 3; b = 3; c = -10;
Δ = b2-4ac
Δ = 32-4·3·(-10)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{129}}{2*3}=\frac{-3-\sqrt{129}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{129}}{2*3}=\frac{-3+\sqrt{129}}{6}
$